Hello Everybody.(adsbygoogle = window.adsbygoogle || []).push({});

I gave a quick look onto the internet but i couldnt get anything interesting.

Heres my problem.

Im solving the differential equation given by:

[tex](-\Delta+k^2)^2u=\delta [/tex]

Where [tex]\delta[/tex] is the dirac delta distribuiton (and u is thought as a distribution as well)

The first step in the book is to apply FT to both sides of the equation...

The result is:

[tex](4\pi^2\xi^2+k^2)^2\hat{u}=1[/tex]

...I do know that the FT of the Laplacian is [tex]-4\pi^2\xi^2[/tex], but when the whole parenthesis is squared, i just can follow it. I dont know how to get that result....

BTW..whats the meaning of [tex]\Delta^2[/tex]?

Any ideas?

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# Fourier transform of laplace operator

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