Frequency Comparator: Design & PLC Elements in Speed Radar

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Frequency comparators can be designed using methods such as bandpass filters for single frequency comparisons or analog spectrum analyzers for multiple frequencies. Digital signal processing (DSP) and Fast Fourier Transform (FFT) techniques can also be employed for detailed frequency analysis of input signals. In speed radar applications, the Doppler shift in the frequency of the return signal is utilized to calculate the speed of moving objects. Additional resources and circuit examples are available for those interested in frequency comparison design. Understanding these components is essential for effective speed radar functionality.
kautilya
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does anyone know a frequency comparator is designed?

also what are the elements of programmable logic control in a speed radar?
 
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kautilya said:
does anyone know a frequency comparator is designed?

also what are the elements of programmable logic control in a speed radar?

The function of determining a signal's frequency content can be accomplished several different ways. If you just have a single frequency that you want to compare an input signal's spectrum against, you can use a simple bandpass filter to tell you how large the signal content is at that frequency in the input waveform.

If you want more information about multiple frequencies in the input waveform, you can use an analog spectrum analyzer circuit (mixer + LPF), or you can digitize the waveform, and use digital signal processing (DSP) and/or Fast Fourier Transform (FFT) processing to give you the signal energy at different frequencies.

As to the RADAR gun question, it is using the Doppler shift in frequency of the return signal to calculate the speed of the reflecting object.

http://en.wikipedia.org/wiki/Radar_gun
 
In addition to Berkeman's answer in paragraph 1, i found the following circuit that highlights a method of achieving frequency comparison.
there is a simple explanation that goes along with it but generally the idea is clear.
http://www.newcircuits.com/circuit.php?id=msr006
 
I am trying to understand how transferring electric from the powerplant to my house is more effective using high voltage. The suggested explanation that the current is equal to the power supply divided by the voltage, and hence higher voltage leads to lower current and as a result to a lower power loss on the conductives is very confusing me. I know that the current is determined by the voltage and the resistance, and not by a power capability - which defines a limit to the allowable...

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