Frequency, inductance, and capacitance

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SUMMARY

The discussion centers on calculating the capacitance required for an oscillator operating at a frequency of 96.9 MHz with an inductance of 1.4 μH. The relevant formula for an LC circuit is used, which relates frequency (f), inductance (L), and capacitance (C) through the equation f = 1 / (2π√(LC)). By rearranging this equation, the capacitance can be determined as C = 1 / (4π²f²L). Substituting the given values results in a capacitance of approximately 0.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

taylorjr
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Homework Statement



The oscillator of a 96.9 MHz FM station has an inductance of 1.4 μH. What is the value of the capacitance?

Homework Equations



I haven't the slightest idea. I've looked through the section in my physics book and looked all over online and I can't find anything.

The Attempt at a Solution



Just looking at the units, a Henry is [tex]\Omega[/tex] * s, and a Farad is s / [tex]\Omega[/tex], so I multiplied the two given values, getting s[tex]^{2}[/tex], then I took the square root, but no luck.
 
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