Fun Car Physics Problem. I swear it's wicked fun

[Iamaskier721]

You are traveling in your 2000 kg car at 9.2 m/s and wish to accelerate to 17.5 m/s in 3.08 seconds, how much work, to the nearest joule, is required?

Okay so i don't even know hwo t ostart this problem. I know I need to find the
initial amount of work being done by the car and then subtract it from the end amount of work. Any help?

 

[cellotim]

Give the formula for work and the formula for energy and it should be obvious.

 

[Iamaskier721]

Well the formula for work is obviously Force times Displacement and the formula for energy is 1/2 mass times the velocity squared. Do I just find the difference in their enery?

 

[cellotim]

Yes, the 3.08 seconds is unnecessary because we are interested in work and not power. The simplest formula for work is, $$W = \Delta E$$, i.e. change in energy.

 

[Iamaskier721]

Ah I finally got it! Thankyou all! The 3.08 seconds was just relevant to the next question which was find the power in watts and that is just work divided by time. Thanks again!