- #1
Karlisbad
- 131
- 0
Is there any Functional equation In functional derivatives so the Feynman Path integral is its solution?.. i mean given:
[tex] A[\Phi]=\int \bold D[\Phi]e^{iS/\hbar} [/tex]
Then A (functional) satisfies:
[tex] G( \delta , \delta ^{2} , B[\phi] )A[\Phi]=0 [/tex]
where B is a known functional and "delta" here is the functional derivative.
[tex] A[\Phi]=\int \bold D[\Phi]e^{iS/\hbar} [/tex]
Then A (functional) satisfies:
[tex] G( \delta , \delta ^{2} , B[\phi] )A[\Phi]=0 [/tex]
where B is a known functional and "delta" here is the functional derivative.