G-force question. amusment park physics

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    G-force Physics
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SUMMARY

The discussion centers on calculating the g-force experienced on the Giant Drop ride at Dreamworld, specifically when increasing its height from 120m to 200m. The user applies the kinematic equations to determine the velocity and time of free fall, ultimately calculating a velocity of 62.1 m/s. The g-force is derived from the acceleration due to gravity, which is -9.8 m/s². The user seeks clarification on the time calculation and the forces experienced during the ride.

PREREQUISITES
  • Understanding of basic physics concepts, including acceleration and free fall
  • Familiarity with kinematic equations
  • Knowledge of g-force calculations
  • Basic grasp of circular motion and centrifugal force
NEXT STEPS
  • Research the effects of ride height on g-force and passenger experience
  • Learn about the physics of circular motion and centrifugal force
  • Explore advanced kinematic equations for varying acceleration scenarios
  • Investigate safety regulations for amusement park rides
USEFUL FOR

This discussion is beneficial for physics students, amusement park engineers, and safety analysts focused on ride design and passenger safety in thrill rides.

JT1993
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hey, i am a year 11 student trying to complete an assignmnt based on the physics in the amusment park 'dreamworld'

i have been ask to change something about a ride and write about safety and thrill factor this would affect, a chose the giant drop ( a free fall ride )

i am planning to change the height of the ride from 120m to 200m , and now trying to calculate g force

so far:

s = -200m
u = 0
v = ?
t = ?
a = -9.8 m/s




on the internet i found an equation for g force:

a / g = g force

a = change in velocity / change in time
g = -9.8




i calculated velocity first

v2 = u2 + 2as
v2 = (0)2 + (2 x -9.8 x - 200)
v2 = 3920
v = 62.1

now i have velocity i tried to work out time

v = u +at
62.61 = o + (-9.8 x t)
62.61 = -9.8 x t
62.61 / -9.8 = t
- 6.39 = t

and that's it i cannot find a way and i am very confused please help i am still learning :(

thank you
 
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:( help?
 
Let's say you're in a cart moving at some velocity, v, let's ignore gravity for now.
This cart sits on a rail, at some point along the track, the rail bends into the shape of a circle of radius R (Its radius of curvature is R).

From the accelerated reference frame of the cart, what force would you feel? (Hint: It would be the centrifugal force)

Once you've answered that question, you can generalize to any curve with a given radius of curvature, and thus find the acceleration the passengers would feel moving at any point along that curve, provided you know their velocity.
 

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