G Magnitude to V magnitude stars in a CCD

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SUMMARY

This discussion focuses on converting instrumental magnitudes from a CCD camera using a g filter to V magnitudes. The conversion formula identified is V = g - 0.03 - 0.42*(g-r), sourced from Windhorst et al. (1991). It is established that to accurately convert g magnitudes to V magnitudes, measurements from an r filter are necessary due to the different wavelength bands. The need for dual-filter measurements is emphasized to achieve precise photometric results.

PREREQUISITES
  • Understanding of CCD imaging techniques
  • Familiarity with photometric concepts
  • Knowledge of astronomical filters (g and r filters)
  • Basic grasp of magnitude systems in astronomy
NEXT STEPS
  • Research the principles of CCD photometry
  • Learn about the effects of different astronomical filters on magnitude measurements
  • Study the paper by Windhorst et al. (1991) for detailed methodologies
  • Explore alternative methods for estimating V magnitudes without r filter data
USEFUL FOR

Astronomers, astrophysics students, and anyone involved in CCD imaging and photometric analysis will benefit from this discussion.

joseamck
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I have astronomical images taken using a CCD camera and telescope using a g filter. In the images I have stars with what is called instrumental magnitudes (from the photon count in each pixel). My question is if there is a way to change this g instrumental magnitude to a real V magnitude.

I have found this:
V = g - 0.03 - 0.42*(g-r)

from
Windhorst, R. W., et al. 1991, ApJ, 380, 362
and http://www.astro.umd.edu/~ssm/ASTR620/mags.html

This is telling me that I needed to have used an r filter on the same images. Is there another way to find the V magnitudes of the stars by only having images taken with a g filter?


Thank you
 
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Not, with any precision. It would help if you told us what your background in photometry is?
 
does it matter what the background is if all images were taken with a g filter? I don't understand the question.
 
When I say "your background in photometry" I'm talking about your personal prior knowledge about the topics covered in the scientific field of photometry.
 
Since the two filters have different wavelength bands, the conversion will depend on the color of the object. That is why you need two different measurements with two different filters to do a conversion. You might find this paper useful. Figure 1 shows the comparison of the filter bands.
 
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Great!
 

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