Derivative of Gamma Function: Finding the Mistake?

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The discussion centers on the incorrect calculation of the derivative of the Gamma function, where the user mistakenly derived with respect to the wrong variable. The correct approach involves using logarithmic differentiation, which reveals that the derivative should be calculated as (d/dz)t^(z-1) = t^(z-1) ln t. The user acknowledges the error and expresses difficulty in calculating the resulting integral for integer parameter values. This highlights the complexities involved in differentiating the Gamma function accurately. The thread emphasizes the importance of proper variable differentiation in mathematical calculations.
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I have tried to calculate the derivative of Gamma function and got a strange result, which
is obviously wrong. Can someone find the mistake?

Definition:
Gamma[z]=Integral[t^(z-1)exp(-t)dt]

Derivative:
(d/dz)Gamma[z]=Integral[(d/dz)t^(z-1)exp(-t)dt]=Integral[(z-1)t^(z-2)exp(-t)dt]=
(z-1)*Gamma[z-1]=Gamma[z]

Looks like gamma solves the equation f'=f, but this can't be true, since only
exponential function solves this equation.
 
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Your problem is with (d/dz)t^(z-1). What you computed is really (d/dt)t^(z-1). You need to use logarithmic differentiation: (d/dz)t^(z-1) = t^(z-1) ln t
 
You are right, I derived with respect to the wrong variable. I wanted to calculate the derivative of gamma at least at integer parameter values, but it seems I won't be able to do this, since I can't calculate the resulting integral.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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