- #1
RMZ
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Homework Statement
I understand why, using Gauss's law, the net charge within a conductor should be zero at any point. However, when I try making a Gaussian surface that is so small so as to enclose a single proton, I cannot see why the enclosed charge should be zero for that situation as well, which seems to throw off everything.
Homework Equations
Electric Flux through a Gaussian surface = Qenc/epsilonnought
The Attempt at a Solution
The electric field at any point on the Gaussian surface should be zero, which means that phiE
=0, which should mean that the enclosed total charge = 0. But if only a proton is within this Gaussian surface how is this possible?