General Centre of mass derivation

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
shaggySS
Messages
2
Reaction score
0
Hello,
It's my first question here. So I'll try to give as much as information as I know

Actually I am stuck with a problem of centre of mass derivation of a triangle with its base on the X axis and symmetric about it.
The base is b and height is H

As far as I know I have to imagine it as a couple of 1d bodies and integrate them.

Thanks
SAGNIK
 
Physics news on Phys.org
Since its symmetric about the X axis the y coordinate needs to be found only.
 
The y- coordinate of the center of gravity of an object with density function [itex]\delta(x,y)[/itex] is
[tex]\frac{\int y \delta(x,y) dxdy}{\int \delta(x, y) dxdy}[/tex]
In particular, if [tex]\delta[/tex] is a constant, it can be factored out of the two integrals and cancelled- that is the "center of gravity" is just the
geometrical "centroid". Here, we can set up a coordinate system so that the origin is at the center of the base of the isosceles triangle, base
along the x- axis, height along the y-axis. The equations of the two slant sides can easily be determined.
 
Last edited by a moderator: