MHB Generalised Quaternion Algebra over K - Dauns Section 1-5 no 19

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The discussion revolves around Exercise 19 from Dauns' "Modules and Rings," which asks to prove that the ring K[I, J] is isomorphic to a ring of 2x2 matrices. Participants express confusion about the mapping of elements in K[I, J] and the specific forms given in the problem. Clarifications highlight that elements a and b belong to K[I], which aids in understanding the isomorphism. One participant, Peter, mentions that he has made progress with the problem thanks to insights from Deveno. The conversation concludes with Peter reflecting on the legacy of John Dauns, noting his passing in 2009.
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In Dauns book "Modules and Rings", Exercise 19 in Section 1-5 reads as follows: (see attachment)

Let K be any ring with [FONT=MathJax_Main]1[FONT=MathJax_Main]∈[FONT=MathJax_Math]K whose center is a field and $$ 0 \ne x, 0 \ne y \in $$ center K are any elements.

Let I, J, and IJ be symbols not in K.

Form the set K[I, J] = K + KI + KJ + KIJ of all K linear combinations of {1, I, J, IJ}.

The following multiplication rules apply: (These also apply in my post re Ex 18!)

$$ I^2 = x, J^2 = y, IJ = -JI, cI = Ic, cIJ = JIc $$ for all $$ c \in K $$

Prove that the ring K[I, J] is isomorphic to a ring of $$ 2 \times 2 $$ matrices as follows:

$$ a + bJ \rightarrow \begin{pmatrix} a & by \\ \overline{b} & \overline{a} \end{pmatrix} $$ for all $$ a,b \in K $$

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I am not sure how to go about this ... indeed I am confused by the statement of the problem. My issue is the following:

Elements of K[I, J] are of the form r = a + bI + cJ + dIJ so we would expect an isomorphism of K[I, J] to specify how elements of this form are mapped into another ring, but we are only told how elements of the form s = a + bJ are mapped. ?

Can someone please clarify this issue and help me to get started on this exercise?

Peter
 
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K[I,J] is naturally isomorphic to K[J]:

a + bI + cJ + dIJ <--> (a+bI) + (c+dI)J
 
Deveno said:
K[I,J] is naturally isomorphic to K[J]:

a + bI + cJ + dIJ <--> (a+bI) + (c+dI)J


Thank you Deveno ... but still thinking

Mind you I (stupidly) missed the point that $$ a, b \in K $$ which your post has made me highly aware of - will go back to this now.

Peter
 
Peter said:
Thank you Deveno ... but still thinking

Mind you I (stupidly) missed the point that $$ a, b \in K $$ which your post has made me highly aware of - will go back to this now.

Peter


Based on Deveno's help I have now worked through a good deal of the problem ... and I am satisfied I now understand it ...

For members of MHB interested in this exercise, I have attached a check of the fact $$ \phi (x, y) = \phi (x) \phi (y) $$ 'works' for $$ {element}_{11} $$ of the isomorphism $$ \phi $$ ...

I must say that John Dauns' is not afraid to set his students at Tulane University a fair amount of symbol manipulation ... :)

Peter
 
Peter said:
Based on Deveno's help I have now worked through a good deal of the problem ... and I am satisfied I now understand it ...

For members of MHB interested in this exercise, I have attached a check of the fact $$ \phi (x, y) = \phi (x) \phi (y) $$ 'works' for $$ {element}_{11} $$ of the isomorphism $$ \phi $$ ...

I must say that John Dauns' is not afraid to set his students at Tulane University a fair amount of symbol manipulation ... :)

Peter

I just looked up Jon Dauns on the Internet and discovered that, very sadly, John Dauns passed away in 2009.

It is a sad loss to algebra ...

Peter
 

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