Geodesic Distance & Maximally Symmetric Spacetimes: Why Does it Matter?

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SUMMARY

The discussion centers on the relationship between physical quantities in maximally symmetric spacetimes and geodesic distances. It establishes that any physical quantity K(t,x,x') in such spacetimes depends solely on the geodesic distance between points x and x'. The conversation highlights the Euclidean plane as a maximally symmetric space, where K(x,y) is constrained by symmetries to depend on (x-y)². The participants express uncertainty about how this dependence alters in the context of a Euclidean disk, particularly regarding the influence of the boundary on K(x,y).

PREREQUISITES
  • Understanding of maximally symmetric spacetimes
  • Familiarity with geodesic distances in differential geometry
  • Knowledge of symmetries in physical systems
  • Basic concepts of Euclidean geometry
NEXT STEPS
  • Research the implications of boundary conditions in Euclidean disks
  • Study the properties of geodesic distances in non-maximally symmetric spacetimes
  • Examine the paper referenced: "https://arxiv.org/pdf/0804.1773.pdf"
  • Explore the mathematical proofs related to symmetries and physical quantities in spacetime
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Physicists, mathematicians, and students interested in the interplay between geometry and physical laws, particularly those studying general relativity and differential geometry.

highflyyer
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Any physical quantity ##K(t,x,x')## on a maximally symmetric spacetime only depends on the geodesic distance between the points ##x## and ##x'##.

Why is this so?

N.B.:

This statement is different from the statement that

The geodesic distance on any spacetime is invariant under an arbitrary coordinate transformation of that spacetime.
 
Last edited:
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highflyyer said:
Why is this so?

Why do you think it is so? Have you found a proof of it?
 
I haven't found a proof of it. I read this in a paper.

This is my understanding of the problem.

The Euclidean plane is a maximally symmetric space with ##3## translation symmetries and ##3## rotation symmetries. Any physical quantity ##K(x,y)## on the Euclidean plane, where ##x## and ##y## are two arbitrary spacetime points, is constrained by the symmetries of the spacetime to depend only on ##(x-y)^{2}##. This is because ##(x-y)## is translation invariant and ##(x-y)^{2}## is rotation invariant. Therefore, the physical quantity ##K(x,y)## depends on the Galilean-invariant geodesic distance ##(x-y)^{2}##.
 
But I am not sure how the dependence changes if we have a Euclidean disk (that is, a plane with a boundary).

My intuition is that the ##K(x,y)## now depends not only on the spacetime points ##x## and ##y##, but also on the 'border.' The dependence is such that ##K(x,y)## for the Euclidean disk tends to ##(x-y)^2## as the 'border' tends to infinity.

But I am not able to carry my intuition any further and write down an explicit form for the dependence of ##K(x,y)## for the Euclidean disk.

It would be really helpful if you share some thoughts here.
 
highflyyer said:
I read this in a paper

What paper? Please give a reference.
 
highflyyer said:
I am not sure how the dependence changes if we have a Euclidean disk (that is, a plane with a boundary).

A plane with a boundary is not maximally symmetric.
 
highflyyer said:
See the final paragraph on page 7 of https://arxiv.org/pdf/0804.1773.pdf.

Ok, this mentions the proposition but doesn't give a proof. Possibly one of the references in that paper does.

Your reasoning in post #3 seems OK to me.
 

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