Geometric Optics- Two Questions

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SUMMARY

The discussion focuses on solving two geometric optics problems involving a concave lens and light refraction through crown glass. For the first problem, the magnification of a 5 cm object placed 20 cm in front of a lens with a power of -2.5 diopters is calculated to be 2/3, confirming the lens is concave. The second problem involves determining the lateral displacement of light striking a rectangular piece of crown glass at a 30-degree angle of incidence, requiring the application of Snell's Law and trigonometric principles.

PREREQUISITES
  • Understanding of the thin-lens equation
  • Knowledge of magnification calculations
  • Familiarity with Snell's Law
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Study the thin-lens equation and its applications in optics
  • Learn about magnification in concave and convex lenses
  • Explore Snell's Law and its implications in light refraction
  • Practice trigonometric calculations related to angles of incidence and refraction
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Students studying optics, physics educators, and anyone interested in understanding lens behavior and light refraction principles.

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1.Determine the magnification of a 5cm object that has been placed 20 cm in front of a lens with a power of -2.5 d?

2. Light strikes a rectangular piece of crown glass with an angle of incidence of 30 degrees. If the block of glass is 10cm, determine the measure of lateral displacement.

Can anyone give me the steps to solving these? I'm kind of having a hard time.:cry:

It would really be appreciated.:shy:
 
Last edited:
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1. use the thin-lens equation to find the image distance, then use the magnification equation to determine the magnification. The "5 cm" is extraneous information.

2. Draw the ray as it refracts through the glass. Find the angle of refraction. Do a little trig.
 
p=-2.5d
f=-1/2.5=-0.4
i/f=i/v-i/u
-2.5=1/v-(-1/(20/100))
-2.5=1/v+5
1/v=-7.5
m=v/u
(1/-7.5)/(-20/100)
(1/-7.5)*-5
2/3
thus, it is a concave lens
 

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