Geometric sequence, determining the value of the first term

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Discussion Overview

The discussion revolves around determining the value of the first term in a geometric sequence given the values of the 3rd and 9th terms. Participants explore the relationships between the terms using the general formula for geometric sequences.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents the equations derived from the geometric sequence formula: -3 = a_1r^2 and -192 = a_1r^8.
  • Another participant suggests that there are two equations with two unknowns and questions how to solve them.
  • A participant expresses uncertainty about finding the common ratio since the terms are not consecutive.
  • There is a suggestion to divide the second equation by the first to find the common ratio.
  • A participant calculates that dividing the second equation by the first yields r^6 = 64, leading to r = 2, but seeks confirmation on this result.
  • Another participant encourages checking the value of a_1 to verify the correctness of the computed common ratio.
  • A participant calculates a_1 as -3/4 based on the value of r they found.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correctness of the calculations or the method to find the common ratio. There are multiple viewpoints on how to approach the problem, and uncertainty remains regarding the final values.

Contextual Notes

Participants express confusion about the method of finding the common ratio when the terms are not consecutive, indicating potential limitations in their understanding of the relationships between the terms.

tug187
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question - if the 3rd and 9th term of a geometric series with a positive common ratio are -3 and -192 respectively, determine the value fo the first term, a.

I kno we using
a_n=a_1r^n-1


From that i got this :

-3 = a_1r^2
-192 = a_1r^8

But I don't kno how I can solve for r or a_1... I also don't know if I even did it right
 
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Well, you have two equations in two unknowns, don't you? How do you generally solve such things?
 
Hurkyl said:
Well, you have two equations in two unknowns, don't you? How do you generally solve such things?

thats what I am wondering.. I don't think the way your thinking of works.. I forgot how to figure out the common ratio that's all i really need to know
 
You need to solve the equations you wrote down to get r=

-3 = a_1r^2
-192 = a_1r^8
 
roger said:
You need to solve the equations you wrote down to get r=

-3 = a_1r^2
-192 = a_1r^8

thats what i don't understand, on other questions i got the common ratio easily by using the term before it but these 2 terms r not after each other so i don't know how to figure them out
to make it more clear its:
-3=a1r2
-192=a1r8
 
tug187 said:
thats what i don't understand, on other questions i got the common ratio easily by using the term before it but these 2 terms r not after each other so i don't know how to figure them out
to make it more clear its:
-3=a1r2
-192=a1r8

What happens if you divide the second equation by the first?
 
d_leet said:
What happens if you divide the second equation by the first?

64 = r6 ?
26 = r6
r = 2?

anyone kno if this is right?
 
Well, if you computed a_1 too, you could check for yourself to see if it's right!
 
Hurkyl said:
Well, if you computed a_1 too, you could check for yourself to see if it's right!

Ok...

ifwe know that term 3 is -3,
a3 = a1*r^3-1
-3 = a1*2^2
-3 = 4*a1
-3/4 = a1

should be right
 

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