Geometric Series: Find 3 Numbers for 5 Components

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Homework Help Overview

The problem involves finding three numbers that form an increasing geometric series with five components, constrained to be between 31 and 496.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the terms in a geometric series, specifically the multiplication by a common ratio (q) to generate successive terms. There is a suggestion to reconsider the operations involved in forming the series.

Discussion Status

The discussion is ongoing, with participants exploring the correct application of geometric series principles. Some guidance has been provided regarding the use of multiplication rather than addition, but no consensus has been reached on the specific numbers or the correct approach.

Contextual Notes

There is an indication that the original poster may be misunderstanding the relationship between the terms of the series, as they mention being "off" with their calculations. The constraints of the problem are also noted, as the numbers must fall within a specific range.

Femme_physics
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Homework Statement



You must enter 3 numbers between 31 and 496 so there will be an increasing geometric series with 5 components.


The Attempt at a Solution



It tells me I'm off. That q=2. But how?

http://img716.imageshack.us/img716/8895/300xk.jpg
 
Last edited by a moderator:
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Hey FP :)

Multiply instead of add?
 
With a geometric series, you multiply by q to get successive terms:

\begin{align*}<br /> a_2 &amp; = a_1 q \\<br /> a_3 &amp; = a_1 q^2 \\<br /> a_4 &amp; = a_1 q^3 \\<br /> a_5 &amp; = a_1 q^4<br /> \end{align*}

Do you see your mistake now?
 
I like Serena said:
Hey FP :)

Multiply instead of add?


w00t! :) I hope I have all the formulas at the test so I can relook them. Thanks, ILS! And vela, too :)
 

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