Geometry Problem: Uniquely Solving for a and b | Elementary Geometry Figure

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Homework Help Overview

The discussion revolves around an elementary geometry problem involving angles a and b in a figure that is suggested to be a rectangle. The original poster seeks to determine if there is a unique solution for a and b based on the given constraints, particularly the relationship a + b = 90 degrees.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the angles in the context of a rectangle and question whether the assumption of right angles is valid. Some attempt to derive relationships between a and b based on isosceles triangles formed by the angles.

Discussion Status

The discussion is ongoing, with participants examining different interpretations of the figure and the assumptions about the angles. Some have proposed that if the figure is indeed a rectangle, then certain relationships can be established, while others suggest that without confirmation of right angles, conclusions about a and b may not hold.

Contextual Notes

There is uncertainty regarding the nature of the figure (whether it is a rectangle) and the validity of the assumptions made about the angles. The original poster notes that the problem does not explicitly ask for the values of a and b, but rather their comparative relationships.

cepheid
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Hi,

This is not really a problem for the template (it is not even homework). I have come across the elementary geometry problem shown in the figure below.

http://img151.imageshack.us/img151/95/geometryproblemvc9.th.png

I am wondering whether there is some way to solve for a and b uniquely. Although I was able to come up with an expression for every single angle in the diagram in terms of a or b, the only constraint I have found so far is the obvious one: a + b = 90 degrees. That alone leads to infinitely many solutions. Wondering whether there was another constraint I had missed, I tried an arbitrary solution a = 40, b = 50, and it works. It seems more likely that any thing in the solution set to a + b = 90 is fine, rather than me having stumbled upon the only unique solution there is.

The problem as stated does not ask for the values of a and b, it asks only whether:

a > b
a < b
a = b
OR
there is not enough info to make a determination


(yes this is one of those stupid GRE "quantitative comparision" questions)

The solution proposed by the GRE people is to exaggerate the difference between the 91 degrees and the 89 degrees by drawing the former angle larger, requiring that the nearly-square rectangle be redrawn as a rectangle much wider than it is tall. Once this has been done, it becomes "clear" that a > b.

I am wondering whether there is a less crude way of arriving at this conclusion (one that makes use of geometric principles)

Thanks
 
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Am I confused? If the figure is supposed to be a rectangle, then all of the triangles are isosceles. So 2a+89=180 and 2b+91=180. a>b. Am I missing something that is making this hard?
 
We don't know that the angles at the corners are right angles.
 
If its an arbitrary quadrilateral then a>b is not necessarily true. Start drawing non-rectangular cases.
 
Oh...yeah.

Dick said:
Am I confused? If the figure is supposed to be a rectangle, then all of the triangles are isosceles. So 2a+89=180 and 2b+91=180. a>b. Am I missing something that is making this hard?

No, I don't think you are missing anything. It was supposed to be a rectangle, so that's the answer. Thanks. :redface:
 

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