Get the Assistance You Need Today | Help Me Please

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Homework Help Overview

The discussion revolves around algebraic simplification problems, specifically involving rational expressions and factoring. The original poster seeks assistance with multiple expressions that require simplification and potential cancellation of common factors.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss various attempts at simplifying expressions, including factoring and combining like terms. There are questions about the correctness of the original poster's setup and the need for clarity in the expressions presented.

Discussion Status

The conversation includes attempts to provide guidance on simplification techniques, with some participants expressing frustration over the original poster's approach. There is a mix of constructive feedback and criticism, with no clear consensus on the best way forward.

Contextual Notes

The original poster indicates a time constraint, needing to submit their work soon, which adds urgency to the discussion. Some participants question the effort put into the problem-solving process by the original poster.

Drama_Queen
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Help me please. Today.. :)

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Last edited:
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You need to show/explain/discuss what YOU'VE tried first.
 


Drama_Queen said:
I tried doing c:

2-x/x^2-x X 6x/(2-x)(1+x)

= x-4x)(1+x)
You have not written the same problem as you show on the Imageshack site.
The denominator in the left expression should be left in factored form, and BTW x(x - 4) is not equal to x^2 - x. If you have a factor in either numerator that is the same as one in either denominator, you can cancel those factors, since an expression over itself equals 1 (provided that the expression isn't equal to zero).
Drama_Queen said:
--------------

I also tried e:

1(x+3)+2(2x+1)/ (2x+1)(x+3)

x+3+4x+2/ (2x+1)(x+3)

5x+5/ (2x+1)(x+3)
Looks fine, but should be written as (5x + 5)/((2x + 1)(x + 3))
Drama_Queen said:
--------------

I tried f too:

6(3-2x)- 3(2x-3) / (2x-3)(3-2x)
Mistake in next line. The numerator should be (18 - 12x - 6x + 9). When you combine like terms, think about factoring this expression, because you might get some cancellation with one of the factors in the denominator.
Drama_Queen said:
18-12x-6x-9 / (2x-3)(3-2x)


-18x+9 / (2x-3)(3-2x)

------------------

I really need you help. It should be submited tomorrow.
 


Drama_Queen said:
I tried doing c:

2-x/x^2-x X 6x/(2-x)(1+x)

= x-4x)(1+x)--------------

I also tried e:

1(x+3)+2(2x+1)/ (2x+1)(x+3)

x+3+4x+2/ (2x+1)(x+3)

5x+5/ (2x+1)(x+3)

--------------

I tried f too:

6(3-2x)- 3(2x-3) / (2x-3)(3-2x)

18-12x-6x-9 / (2x-3)(3-2x)-18x+9 / (2x-3)(3-2x)

------------------

I really need you help. It should be submited tomorrow.

Why don't you try a, and b? Are they that difficult?

All of the problems here are just calculations, basic simplification. Well, if you find anywhere unclear in the concept of simplification, then I'll be more than willing to help you by explaining them to you (and then, of course, the task to solve all of the problem posted if yours).

But if you are just too lazy to solve your problems, then, how can you expect us to solve them for you? Are we paid anything for doing that? And, will it be of any benefit?

Please don't make it up like you've been thinking all days long about these problems, while in fact, you just spent, like 5 minutes to type in all those craps and clicked on the Post Message button.
 


^^ WHAT THE HELL?
Thank you for your help .. I won't waste my time on this forum.
I tried but couldn't make it :). and if you want to get paid then **** off :)
 


I would suggest you look at the post by Mark44 rather than the (incredibly inappropriate) post by VietDao29 before you write this forum off.
 

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