The line y = x + 2 intersects the curve 4y + 3x^2 = 7 in two places.(adsbygoogle = window.adsbygoogle || []).push({});

a) Find the coordinates of the two points of intersections.

>Sub. y = x + 2 to 4y + 3x^2 = 7

>4(x+2) + 3x^2 = 7

>4x + 8 + 3x^2 -7 = 0

>3x^2 + 4x -1 = 0

>x = -1 and - 1/3

>y = x + 2

>so y = 1 or 5/3

The straight line y = f(x) has gradient 3 and intersects the curve 4y + 3x^2 = 7 at one point only.

b) Find f(x).

>???

c) Hence find the coordinates of the point of intersection between y = f(x) and 4y + 3x^2 =7

>???

:(

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# Homework Help: Can someone correct my questions and help me please.

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