Getting the maximum and the minimum with now

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The discussion focuses on solving a cryptarithmetic equation involving the three-digit integer "NOW" represented by the digits N, O, and W. The equation is defined as (NOW) * (NOW) = (xxxxxNOW)/1983, where each x can be any decimal digit. The solution was derived through brute force methods, leading to the identification of the minimum and maximum values of "NOW". The specific values were not disclosed in the discussion.

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In the following cryptarithmetic equation, each of the x’s represent a decimal digit, whether same or different, and “NOW” represents a three digit positive integer with no leading zero. Each of N, O and W represent a decimal digit, whether same or different.

(N O W) * (N O W)
= (x x x x x x N O W)/1983

What are the respective minimum value and the maximum value of “NOW”?
 
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There are three values of NOW that satisfy the equation:
272: 272 * 272 == 146710272 / 1983
375: 375 * 375 == 278859375 / 1983
647: 647 * 647 == 830101647 / 1983
272 is the minimum and 647 is the maximum.
This was found by brute force.
 
Also found by Brute Force:
There are three solutions:
n=2 o=7 w=2 => now*now*1983=146710272
n=3 o=7 w=5 => now*now*1983=278859375
n=6 o=4 w=7 => now*now*1983=830101647

Thus, the minimum value for now is 272 and the maximum is 647.
 

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