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Divide by one digit numbers by two digit numbers, and add to get 1

  1. Feb 4, 2009 #1
    Substitute each of the letters by a different decimal digit from 1 to 9 to satisfy this cryptarithmetic equation:

    A/(BC) + D/(EF) + G/(HI) = 1

    where, each of BC, EF and HI represents a two digit positive integer.
  2. jcsd
  3. Feb 4, 2009 #2
    This is my answer! [edit and its wrong]
    8/16 + 9/27 + 5/30 damn just realised you cant have "0"

    after 15 mins i cannot find a solution, and am starting to believe there isnt one!!
    Last edited: Feb 4, 2009
  4. Feb 5, 2009 #3
    It's possible, but it ain't pretty. As in, 2 of the fractions you'll need aren't reducible to common things like 1/3 or 1/8, etc. The other fraction's pretty normal.

  5. Feb 5, 2009 #4
    oh man... i was pretty close to getting this right... i was on the right track at least.. but then i got pissed and looked it up instead.. good problem!
  6. Feb 5, 2009 #5
    I got this one:
    5/34 + 7/68 + 9/12
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