Given ∆Hf = -607 kJ/mol and S = 417 J, find ∆H and ∆S

  • Thread starter Thread starter AMan24
  • Start date Start date
Click For Summary

Discussion Overview

The discussion revolves around calculating the change in enthalpy (∆H) and change in entropy (∆S) for the reaction involving nickel and carbon monoxide to form nickel tetracarbonyl, Ni(CO)4. Participants are seeking guidance on how to approach the problem using given thermodynamic values.

Discussion Character

  • Homework-related
  • Technical explanation

Main Points Raised

  • One participant expresses uncertainty about how to solve the problem due to a lack of prior instruction in thermodynamics.
  • Another participant suggests looking up relevant formulas and provides links to external resources for thermodynamic concepts.
  • A request for clarification on the definitions of ∆H° and ∆S° is made by one participant.
  • Several participants ask for an image of the question to better understand the context.
  • One participant acknowledges having a textbook but prefers not to read an entire chapter for a single question, seeking a more direct explanation of the equations needed.

Areas of Agreement / Disagreement

Participants generally agree on the need for additional resources and clarification, but there is no consensus on how to approach the calculations or the specific formulas to use.

Contextual Notes

Participants express varying levels of familiarity with thermodynamic principles, and there is an indication that some foundational knowledge may be missing, which could affect their ability to solve the problem.

AMan24
Messages
58
Reaction score
2

Homework Statement


Ni (s) + 4 CO(g) ↔ Ni(CO)4(g)

For Ni(CO)4(g), ∆Hf = -607 kJ/mol and S = 417 J/mol⋅K at 298 K. Using these values and data in the Appendix of your text, calculate ∆H and ∆S for the above reaction.

Homework Equations


no idea

The Attempt at a Solution


I don't know how to solve this, because my lab class somehow ended up a week ahead of lecture, so i haven't even learned thermodynamics yet.

I think i found the answers online but i need to show work.
∆S°= -409.5 J/K
∆H° =−160.8 kJ

I'm trying to look up formulas right now and find something i can use.
 
Physics news on Phys.org
AMan24 said:
I don't know how to solve this, because my lab class somehow ended up a week ahead of lecture, so i haven't even learned thermodynamics yet.
Don't you have a textbook?

We can't do your work for you, but have a look at http://chem.libretexts.org/Core/Phy...tions/Enthalpy/Standard_Enthalpy_Of_Formation
https://www.chem.tamu.edu/class/majors/tutorialnotefiles/enthalpy.htm
https://www.chem.tamu.edu/class/majors/tutorialnotefiles/gibbs.htm
 
Last edited by a moderator:
Hae can you define it clearly ∆H° is for and also∆s°
 
Can you send the questions image
 
Timakki said:
Can you send the questions image

heres the image if it helps

boBmFEm.png
 
DrClaude said:
Don't you have a textbook?
We can't do your work for you, but have a look at

Yeah i don't want to come across like I'm hoping someone will do the work for me, i really try to avoid posting things like this.

I do have a textbook, but i didn't want to read the entire chapter in one night so i could answer one question. I was hoping someone could just tell me the equations and i could plug them in.

I'll take a look at the links you posted tomorrow.
 
Last edited by a moderator:

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
3
Views
3K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K