# Given ∆Hf = -607 kJ/mol and S = 417 J, find ∆H and ∆S

1. Nov 15, 2016

### AMan24

1. The problem statement, all variables and given/known data
Ni (s) + 4 CO(g) ↔ Ni(CO)4(g)

For Ni(CO)4(g), ∆Hf = -607 kJ/mol and S = 417 J/mol⋅K at 298 K. Using these values and data in the Appendix of your text, calculate ∆H and ∆S for the above reaction.

2. Relevant equations
no idea

3. The attempt at a solution
I don't know how to solve this, because my lab class somehow ended up a week ahead of lecture, so i haven't even learned thermodynamics yet.

I think i found the answers online but i need to show work.
∆S°= -409.5 J/K
∆H° =−160.8 kJ

I'm trying to look up formulas right now and find something i can use.

2. Nov 15, 2016

### Staff: Mentor

Don't you have a textbook?

We can't do your work for you, but have a look at http://chem.libretexts.org/Core/Phy...tions/Enthalpy/Standard_Enthalpy_Of_Formation
https://www.chem.tamu.edu/class/majors/tutorialnotefiles/enthalpy.htm [Broken]
https://www.chem.tamu.edu/class/majors/tutorialnotefiles/gibbs.htm [Broken]

Last edited by a moderator: May 8, 2017
3. Nov 15, 2016

### Timakki

Hae can you define it clearly ∆H° is for and also∆s°

4. Nov 15, 2016

### Timakki

Can you send the questions image

5. Nov 15, 2016

### AMan24

heres the image if it helps

6. Nov 15, 2016

### AMan24

Yeah i don't want to come across like i'm hoping someone will do the work for me, i really try to avoid posting things like this.

I do have a textbook, but i didn't want to read the entire chapter in one night so i could answer one question. I was hoping someone could just tell me the equations and i could plug them in.

I'll take a look at the links you posted tomorrow.

7. Nov 15, 2016

### Timakki

Last edited by a moderator: May 8, 2017