Gram-Schimidt orthonormalization for three eigenvectors

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Discussion Overview

The discussion revolves around the Gram-Schmidt orthonormalization process for three eigenvectors of a matrix. Participants are examining the correctness of the orthogonalization equations presented, particularly focusing on the third equation, while also addressing issues related to notation and subscripts.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant presents the orthogonalization equations for three eigenvectors and asks for verification of the third equation's correctness.
  • Another participant suggests that the original vectors should be edited to have different subscripts to avoid confusion.
  • There is a discussion about the implications of using the same subscript for multiple vectors, with one participant noting that it indicates they are the same vector.
  • A later reply proposes checking the correctness of the third eigenvector by verifying the orthogonality condition with the Kronecker delta.
  • Participants acknowledge a typo in the subscripts of the eigenvectors, but the implications of this on the orthogonalization process are not resolved.

Areas of Agreement / Disagreement

Participants generally agree that there is a typo in the subscripts of the eigenvectors, but the correctness of the third orthogonalization equation remains contested and unresolved.

Contextual Notes

The discussion highlights potential confusion arising from notation and the need for clarity in mathematical expressions, but does not resolve the correctness of the orthogonalization equations.

Wrichik Basu
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Say I have a matrix ##A## and it has three eigenvectors ##|\psi_1\rangle##, ##|\psi_2\rangle## and ##|\psi_3\rangle##. I want to orthogonalize these. Say my orthogonalized eigenvectors are ##|\phi_1\rangle##, ##|\phi_2\rangle## and ##|\phi_3\rangle##.
$$
\begin{eqnarray}
|\phi_1\rangle = \frac{|\psi_1\rangle}{|| \psi_1 ||} \\
\text{ } \nonumber \\
\phi_2 = \dfrac{ \left\{| \psi_2\rangle - \langle\phi_1 | \psi_2\rangle |\phi_1\rangle \right\} }{|| \{ \cdots \} ||} \\
\text{ } \nonumber \\
\phi_3 = \dfrac{ \left\{| \psi_3\rangle - \langle\phi_1 | \psi_3\rangle |\phi_1\rangle - \langle\phi_2 | \psi_3\rangle |\phi_2\rangle \right\} }{|| \{ \cdots \} ||}
\end{eqnarray}$$
Our teacher didn't explain this at all. I learned from this video, where the professor has done upto Eqn. (2) only. Can you check whether the third equation above is correct or not?
 
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Wrichik Basu said:
Say I have a matrix ##A## and it has three eigenvectors ##|\psi_1\rangle##, ##|\psi_1\rangle## and ##|\psi_1\rangle##. I want to orthogonalize these. Say my orthogonalized eigenvectors are ##|\phi_1\rangle##, ##|\phi_2\rangle## and ##|\phi_3\rangle##.
$$
\begin{eqnarray}
|\phi_1\rangle = \frac{|\psi_1\rangle}{|| \psi_1 ||} \\
\text{ } \nonumber \\
\phi_2 = \dfrac{ \left\{| \psi_2\rangle - \langle\phi_1 | \psi_2\rangle |\phi_1\rangle \right\} }{|| \{ \cdots \} ||} \\
\text{ } \nonumber \\
\phi_3 = \dfrac{ \left\{| \psi_3\rangle - \langle\phi_1 | \psi_3\rangle |\phi_1\rangle - \langle\phi_2 | \psi_3\rangle |\phi_2\rangle \right\} }{|| \{ \cdots \} ||}
\end{eqnarray}$$
Our teacher didn't explain this at all. I learned from this video, where the professor has done upto Eqn. (2) only. Can you check whether the third equation above is correct or not?
I suggest you edit your three original vectors.
 
Michael Price said:
I suggest you edit your three original vectors.
You mean to say that I should write them such that they are orthogonal to each other?
 
Wrichik Basu said:
You mean to say that I should write them such that they are orthogonal to each other?
Write them in such a way that they have different subscripts. :oldsmile:
 
kuruman said:
Write them in such a way that they have different subscripts. :oldsmile:
:olduhh: Went tangentially past my brain. How would different subscripts matter?
 
Wrichik Basu said:
:olduhh: Went tangentially past my brain. How would different subscripts matter?
You used the same subscript ##_1## for all three vectors.
 
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Wrichik Basu said:
Say I have a matrix ##A## and it has three eigenvectors ##|\psi_1\rangle##, ##|\psi_1\rangle## and ##|\psi_1\rangle##.
If they have the same subscript, they are the same vector - it's just a typo fix. You can check whether you have the correct expression for the third eigenvector by seeing if ##\langle \phi_3|\phi_j\rangle\ = \delta_{3j}.##
 
kuruman said:
If they have the same subscript, they are the same vector - it's just a typo fix.
Fixed typo.
 

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