Graph descriptions of velocity, acceleration, speed and time

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For an object with constant positive acceleration, the displacement can be determined by taking the integral of the velocity vs. time graph, as this gives the area under the curve, representing displacement. In contrast, for an object moving with constant positive velocity, the displacement vs. time graph is linear, with the slope equal to the velocity. The discussion emphasizes the importance of understanding the relationship between derivatives and integrals in the context of motion graphs. Clarification on these concepts is sought to better grasp the underlying principles. Understanding these graph relationships is crucial for analyzing motion effectively.
asz304
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I can't understand the choices or the questions properly. And I want to know which of the following is right. I would appreciate it if you gave a hint or explanation. Thanks


1)For an object moving with constant positive acceleration, the displacement over a period of time could be found by taking:
a) integral of the velocity vs time graph.
b)integral of the acceleration vs time graph.
c)derivative of the velocity vs time graph.
d)derivative of the acceleration vs time graph.

2)For an object moving with constant positive velocity, the displacement vs time graph is:
a)parabolic with an intercept of zero.
b) linear with slope which is equal to the acceleration.
c)linear with slope which is equal to the velocity.
d)horizontal.


Sorry that I didn't add the template. But my question is just about understanding the graphs.
 
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asz304 said:
1)For an object moving with constant positive acceleration, the displacement over a period of time could be found by taking:
a) integral of the velocity vs time graph.
b)integral of the acceleration vs time graph.
c)derivative of the velocity vs time graph.
d)derivative of the acceleration vs time graph.

For this one, if you took the derivative of a displacement-time graph, the derivative would give s/t, which is a velocity.

If you took the integral of graph, you get the area under it, the units will be the product of the axes' units.

asz304 said:
2)For an object moving with constant positive velocity, the displacement vs time graph is:
a)parabolic with an intercept of zero.
b) linear with slope which is equal to the acceleration.
c)linear with slope which is equal to the velocity.
d)horizontal.

Well if the velocity is constant and you know that v=ds/dt then ds/dt = constant. So if you integrate that what do you get?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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