- #1
aleronLolli
I have collected data on a car accelerating down a straight track. I graphed it Position vs Time. Then I found the tangent slope at 5 points along the curve and plotted them as velocity. But then I linearized the position vs Time graph (position vs Time^2.) However, the slope of the velocity vs Time graph i got from taking the slope of the tangents was about double of what I got from linearization. This doesn't make sense to me...
Equations:
Position vs Time:
x = 9.396x^2-1.188x+6.014
Velocity vs Time: (from tangent slopes)
18.7798
Position vs Time^2: (from linearization)
9.188
Equations:
Position vs Time:
x = 9.396x^2-1.188x+6.014
Velocity vs Time: (from tangent slopes)
18.7798
Position vs Time^2: (from linearization)
9.188