Graph descriptions of velocity, acceleration, speed and time

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SUMMARY

The discussion centers on understanding the relationships between displacement, velocity, and acceleration in physics, specifically through the analysis of graphs. For an object with constant positive acceleration, the displacement can be determined by taking the integral of the velocity vs. time graph. Conversely, for an object moving with constant positive velocity, the displacement vs. time graph is linear, with a slope equal to the velocity. These conclusions clarify the mathematical operations needed to interpret motion graphs accurately.

PREREQUISITES
  • Understanding of basic calculus concepts, including integration and differentiation.
  • Familiarity with kinematic equations and their graphical representations.
  • Knowledge of the relationship between displacement, velocity, and acceleration.
  • Ability to interpret velocity vs. time and displacement vs. time graphs.
NEXT STEPS
  • Study the principles of kinematics in physics, focusing on motion graphs.
  • Learn about the integral calculus applications in physics, particularly in motion analysis.
  • Explore the concept of derivatives in the context of velocity and acceleration.
  • Review examples of displacement vs. time graphs for various types of motion.
USEFUL FOR

Students of physics, educators teaching kinematics, and anyone interested in understanding motion through graphical analysis will benefit from this discussion.

asz304
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I can't understand the choices or the questions properly. And I want to know which of the following is right. I would appreciate it if you gave a hint or explanation. Thanks


1)For an object moving with constant positive acceleration, the displacement over a period of time could be found by taking:
a) integral of the velocity vs time graph.
b)integral of the acceleration vs time graph.
c)derivative of the velocity vs time graph.
d)derivative of the acceleration vs time graph.

2)For an object moving with constant positive velocity, the displacement vs time graph is:
a)parabolic with an intercept of zero.
b) linear with slope which is equal to the acceleration.
c)linear with slope which is equal to the velocity.
d)horizontal.


Sorry that I didn't add the template. But my question is just about understanding the graphs.
 
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asz304 said:
1)For an object moving with constant positive acceleration, the displacement over a period of time could be found by taking:
a) integral of the velocity vs time graph.
b)integral of the acceleration vs time graph.
c)derivative of the velocity vs time graph.
d)derivative of the acceleration vs time graph.

For this one, if you took the derivative of a displacement-time graph, the derivative would give s/t, which is a velocity.

If you took the integral of graph, you get the area under it, the units will be the product of the axes' units.

asz304 said:
2)For an object moving with constant positive velocity, the displacement vs time graph is:
a)parabolic with an intercept of zero.
b) linear with slope which is equal to the acceleration.
c)linear with slope which is equal to the velocity.
d)horizontal.

Well if the velocity is constant and you know that v=ds/dt then ds/dt = constant. So if you integrate that what do you get?
 

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