Graph {(x, y) ∈ R+² : X ≥ X’ >0, Y ≥ Y’ > 0}

  • Thread starter Thread starter 939
  • Start date Start date
  • Tags Tags
    Graph
Click For Summary

Homework Help Overview

The problem involves graphing the consumption set of a consumer defined by the inequalities {(x, y) ∈ R+² : X ≥ X’ >0, Y ≥ Y’ > 0}. The original poster seeks to understand the graphical representation without needing a complete graph.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the inequalities, particularly what X ≥ X’ > 0 and Y ≥ Y’ > 0 mean in the context of the graph. There is an exploration of the graph's location in the Cartesian plane and the nature of the points involved.

Discussion Status

Some participants have offered insights into the graphical representation, noting that the graph will be in the first quadrant and discussing the concept of an angle formed by the constraints. There is ongoing exploration of the implications of the inequalities, with some questioning the nature of the points approaching zero.

Contextual Notes

Participants mention that the points can touch zero but clarify that the graph approaches (0,0) without including it. There is also a discussion about the convexity and boundedness of the set, although this remains a point of inquiry rather than a conclusion.

939
Messages
110
Reaction score
2

Homework Statement



The consumption set of a consumer is: {(x, y) ∈ R+² : X ≥ X’ >0, Y ≥ Y’ > 0}. Graph it.

I am only wondering how it looks, don't need a copy of the graph.

Homework Equations



{(x, y) ∈ R+² : X ≥ X’ >0, Y ≥ Y’ > 0}

The Attempt at a Solution



This first part, (x, y) ∈ R+², tells me it will be on the top right part of a Cartesian graph. The points can touch 0. But I am not sure what X ≥ X’ > 0, Y ≥ Y’ > 0 means. We are doing sets and convexity.

The first x value is greater than the second, which are both greater than zero? And the same for Y? 0_o
 
Physics news on Phys.org
Hi, 939

I'll try to cast light on this question ;)

First, let us consider a point in R² (X',Y'), such as X’ >0, Y’ > 0. Therefore, our graph will be in the first quadrant.

Second, What does mean: X ≥ X' and Y ≥ Y’?. It represent an angle in the space. The vertex of the angle is the point (X',Y'), and the angles lines will be the straight lines X=X' and Y=Y' accordingly with the constraints.

I need draw it, but, now I can't.

Is this useful?

Regards
 
939 said:
The points can touch 0.

From the conditions stated, the (0,0) would be represented with an open point. the graph approaches this point but never touches it.

As for the conditions, X \geq X' > 0, I think this means that for every X defined, there is an X' between that number and 0. It says something about the "neighborhood" near the point x = 0. Say, if you are at the point x = 0.0001, there is still a smaller point that is greater than 0. Yet, you never have x =0.

In reality this might not make sense, because when would you say that you have 0.0000001 dollars?

That's my take on it. I hope it helps.
 
Grufey said:
Hi, 939

I'll try to cast light on this question ;)

First, let us consider a point in R² (X',Y'), such as X’ >0, Y’ > 0. Therefore, our graph will be in the first quadrant.

Second, What does mean: X ≥ X' and Y ≥ Y’?. It represent an angle in the space. The vertex of the angle is the point (X',Y'), and the angles lines will be the straight lines X=X' and Y=Y' accordingly with the constraints.

I need draw it, but, now I can't.

Is this useful?

Regards

Thanks! My final question is would you be able to say if the set is convex, closed or bounded?
 
The set is convex due to every pair of points can be linked with a continuous line. Also is closed, because the condition greater or EQUAL. Accordingly with the definition, the complementary set is open. And finally the set is not bounded, it's wonder, there isn't any contidion about the maximum of X or Y.

Regards!
 

Similar threads

Replies
8
Views
5K
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 8 ·
Replies
8
Views
11K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K