MHB Graphics Coordinate: Is This Correct?

squexy
Messages
18
Reaction score
0
View attachment 2983

The answer is E.

Since the line is passing the parable at x = 1 and 2 I used between these values to satisfy the inequality(x − 1)4< (x − 1)X = 1,5

(1,5 -1)4 < (1,5 -1)
0,0625 < 0,5

Is this correct?
 

Attachments

  • asdhiausdh.jpg
    asdhiausdh.jpg
    16.8 KB · Views: 92
Mathematics news on Phys.org
I would begin by finding the $x$-values for which the two graphs intersect. We can do this by equating the two functions:

$$(x-1)^4=x-1$$

$$(x-1)^4-(x-1)=0$$

Now, what do you get when you factor?
 
I was going to type exactly what MarkFL did, but he beat me at it :p

I also want to note that the question has graciously graphed the curves for us, and by inspection, we see that $y=(x-1)^4$ is under the line $y=x-1$ on the interval $(1, 2)$ only, which is the only interval that satisfies your inequality.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.

Similar threads

Replies
3
Views
2K
Replies
7
Views
1K
Replies
4
Views
2K
Replies
4
Views
2K
Replies
1
Views
2K
Replies
2
Views
407
Replies
1
Views
527
Back
Top