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Graphing the V vs I relationship of diode using Square wave

  • Thread starter PH6
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Homework Statement


I am having trouble understanding what this picture is showing.
UUMRkN9.png
[/B]

I know that in the case of a sine wave, the voltage below zero will not conduct much if it does not drop past the breakdown region. On the other hand, it will start to conduct and grow exponentially at about .5-.7 V. However, when I tried the XY(I vs V) mode for a zener diode this is the graph I got. What is going on at each dot?

Homework Equations


I = Io (e^((qV)/(nkT)) -1)
k = 1.38 *10 ^-23
 

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