Graphing the V vs I relationship of diode using Square wave

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
Sign up Log in
1 reply · 2K views
PH6
Messages
1
Reaction score
0

Homework Statement


I am having trouble understanding what this picture is showing.
UUMRkN9.png
[/B]

I know that in the case of a sine wave, the voltage below zero will not conduct much if it does not drop past the breakdown region. On the other hand, it will start to conduct and grow exponentially at about .5-.7 V. However, when I tried the XY(I vs V) mode for a zener diode this is the graph I got. What is going on at each dot?

Homework Equations


I = Io (e^((qV)/(nkT)) -1)
k = 1.38 *10 ^-23
 
Physics news on Phys.org