Graphing y=-e^x: What Am I Looking At?

[poohbear1986]

ok i was graphing y=-e^x e=2.1783 and i got this up and down line growing from negative to positve, i have no clue what the hell I am looking at, I've attached what i got tell if I am right or wrong, point in the right direction if you could

 

[JasonRox]

Take the graph of e^x and flip it upside down.

 

[poohbear1986]

thank you that was driving me nuts

 

[Integral]

The graph you have posted is NOT - e^x

 

[HallsofIvy]

Since you don't say HOW you got that graph, there's not much more we can tell you!
(It looks to me something like y= e^xcos(x).)

 

[Moo Of Doom]

It looks to me like a naive attempt at (-e)^x, judging from the oscillations. Of course, the points between the integers are all wrong. That MAY have been the logic behind it, but I don't know...

 

[Diffy]

poohbear, there is still some confusion. Are you trying to graph (-e)^x or -(e^x). There is a big difference, and writing -e^x is slightly ambiguous (although it implies the latter of the two I wrote).

Moo Of Doom, you are right it looks like (-e)^x (with connecting lines drawn in the undefined parts) but when x is 2 f(x) should be around 7.4 and in his document 4 < f(2) < 6 which actually satisfies neither of the two possibilities mentioned.

 

[Moo Of Doom]

when x is 2 f(x) should be around 7.4 and in his document 4 < f(2) < 6 which actually satisfies neither of the two possibilities mentioned.

I thought it was odd too, but when you look at the original post, he says

graphing y=-e^x e=2.1783 and i got this

and 2.1782² is about 4.74. I think he mistyped his value for e when he plotted the points as well. Makes everything pretty confusing, doesn't it?