Calculating Gravitational Force Between a Doctor and a Baby

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The discussion centers on calculating the gravitational force between a doctor and a baby using the formula F=G(m1m2)/r^2. A participant initially miscalculated the force by using an incorrect distance of 0.5 meters instead of the correct 1 meter. Clarification was provided that the radius in the formula should represent the distance between the centers of the two masses. The conversation highlights the importance of using accurate measurements in gravitational calculations. Ultimately, the focus remains on the gravitational influence of the doctor compared to planetary effects at birth.
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Some believe that the positions of the planets at the time of birth influence the newborn. Others deride this and say that the gravitational force exerted on a baby by the obstetrician is greater than that exerted by the planets. To check this claim, first calculate the gravitational force exerted on a 5.7 kg baby by a 87.9 kg doctor who is 1.0 m away.


ok so i am going to use the formula F=G(m1m2)/r^2 and that would be

F=6.67x10^-11(87.9*5.7)/.5^2 which yeilds 1.32 x10^-7 N which is not the right answer

what am i doing wrong
 
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You have 0.5 for your distance. It should be the 1 m. It is the total distance between the objects you need here.
 
time to call in a replacement--seriously if the center of gravity between the doc and the mom is a meter, those are long forceps. just a joking aside.
 
the equation calls for the radius squared and so i was using .5^2
 
Rasine said:
the equation calls for the radius squared and so i was using .5^2
I think the radius is the distance between the two objects centers. This is different than how we usu think of circles and distance.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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