Gravimetric Analysis to calculate wgt%?

  • Thread starter Thread starter Antonio8
  • Start date Start date
  • Tags Tags
    Analysis
Click For Summary
SUMMARY

The discussion focuses on calculating the weight percentage of AgNO3 in a sample containing AgNO3 and Hg2(NO3)2 using gravimetric analysis. A 0.5330-g sample is dissolved, and the metal cations are precipitated as cobalticyanide salts, resulting in a precipitate mass of 0.5571 g. To determine the weight percentage of AgNO3, participants suggest using two independent equations based on the number of moles of Ag and Hg2, but caution that the system may be ill-conditioned or dependent, complicating the solution process.

PREREQUISITES
  • Understanding of gravimetric analysis techniques
  • Knowledge of stoichiometry and molar mass calculations
  • Familiarity with chemical equations and precipitation reactions
  • Experience with solving systems of equations in chemistry
NEXT STEPS
  • Study the principles of gravimetric analysis in detail
  • Learn how to derive and solve systems of equations in chemical contexts
  • Explore the concept of gravimetric factors in precipitation reactions
  • Investigate methods for handling ill-conditioned systems in analytical chemistry
USEFUL FOR

Chemistry students, analytical chemists, and professionals involved in quantitative analysis and gravimetric methods will benefit from this discussion.

Antonio8
Messages
2
Reaction score
0
A solid 0.5330-g sample which contains only AgNO3(s) and Hg2(NO3)2(s) is dissolved in aqueous medium and the metal cations are precipitated as a mixture of the respective insoluble cobalticyanide salts.
3Ag+(aq) + Co(CN)63−(aq) → Ag3[Co(CN)6](s)
3Hg22+(aq) + 2Co(CN)63−(aq) → (Hg2)3[Co(CN)6]2(s)
The washed and dried precipitate has mass 0.5571 g.
What was the wt% of AgNO3 in the original sample?I tried to solve this using (weight precipitate)*(gravimetric factor)(100) / weight of sample but i got the wrong answer!? can someone please shed some light on this for me !?
 
Physics news on Phys.org
Antonio8 said:
I tried to solve this using (weight precipitate)*(gravimetric factor)

Which gravimetric factor? Your precipitate is a mixture of TWO solids.

The idea behind this type of the question is to write two independent equations - for example assume nAg (number of moles of Ag) and nHg2 are your unknowns. Express masses of the initial and final mixtures using these numbers of moles (and respective molar masses) and you have two equations in two unknowns - just solve.

But I have a feeling it won't work as expected in this case, as the system of equations is ill-conditioned (or perhaps they are even just dependent).
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
8K
  • · Replies 1 ·
Replies
1
Views
8K