1) A 0.25kg book rest on a table. A downward force of 9.5 N is exerted on the top of the book by a hand pushing down on the book.
2)what is the size of the normal force exerted by the table on the book
The Attempt at a Solution
1) what I did 0.25kg*9.81m/s^2= 2.4525N and I then 2.4525N+9.5N= 11.95N
2) wouldn't the normal force be equal to the weight(gravity) so wouldn't the answer be 11.95N or could I subtract 11.95 from 9.5N?