Gravitational Force: Mass & Distance Impact

Click For Summary
SUMMARY

The gravitational force between two planets is determined by the equation F_{g} = G m_{1}m_{2}/d^{2}. When both masses are doubled while maintaining the same distance, the gravitational force quadruples. For example, using the gravitational constant G = 6.67E-11, a mass of planet 1 at 200,000 kg, and planet 2 at 40,000 kg with a distance of 10,000 m, the initial force calculated is 5.336E-9. Doubling the masses results in a force of 2.1344E-8, confirming that the force increases by a factor of four.

PREREQUISITES
  • Understanding of gravitational force equations
  • Familiarity with the gravitational constant (G)
  • Basic algebra for manipulating equations
  • Knowledge of mass and distance in physics
NEXT STEPS
  • Study the implications of the gravitational constant (G) in different contexts
  • Explore gravitational force calculations with varying distances
  • Learn about the effects of mass on gravitational interactions in astrophysics
  • Investigate real-world applications of gravitational force equations in satellite technology
USEFUL FOR

Students of physics, educators teaching gravitational concepts, and anyone interested in the mathematical relationships governing celestial mechanics.

LoveKnowledge
Messages
51
Reaction score
0
1. Show that the gravitational force between two planets is quadrupled if the masses of both planets are doubled but the distance between them stays the same.



2. F = G m1m2/d2 ??



3. confused...
 
Physics news on Phys.org


Okay let's say that we have the following:

G (Gravitational constant) = 6.67E-11
mass of planet 1 = 200,000 kg
mass of planet 2 = 40,000 kg
lets say that the distance r = 10,000 m
all are numbers I just randomly made up

Using the equation: F_{g} = \frac{Gm_{1}m_{2}}{r^{2}}

we just plug in and find that the Force of gravity is:

\frac{(6.67E-11)(200000)(40000)}{(10000)^{2}} which gives 5.336E-9

If we double the masses but keep the distance between them the same:

\frac{(6.67E-11)(400000)(80000)}{(10000)^{2}} gives the value 2.1344E-8


If we divide the force with the doubled masses by the original force:

\frac{2.1344E-8}{5.336E-9} = 4

Thus the gravitational force has been increased by a factor of 4, and quadrupled. HOWEVER THIS IS ONLY AN EXAMPLE, AND PROBABLY NOT WHAT THE QUESTION IS ASKING.


Most likely, the question is asking for some algebra actually showing that doubling the masses results in quadrupled force.


Start with

F_{g} = \frac{Gm_{1}m_{2}}{r^{2}}

the question asks you to show that if the masses are doubled, then the force of gravity
quadruples

so just double the masses and do some algebra to show that either:
a)the second force is 4 times greater than the original force or
b)the original force is 1/4 the second force

Here I'll even get you started:

F_{g2} = \frac{G(2m_{1})(2m_{2})}{r^{2}} = ?
 
Last edited:


thx so much!
 

Similar threads

Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 28 ·
Replies
28
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
15
Views
2K
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K