Gravitational Potential Energy of a System

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SUMMARY

The discussion focuses on calculating the gravitational potential energy of a system consisting of three particles, each with a mass of 1.90 g, arranged at the corners of an equilateral triangle with sides measuring 31.0 cm. The potential energy formula used is U = -(Gm1m2)/r, where G is the gravitational constant (6.67 x 10^-11 Nm^2/kg^2). The initial calculation yielded a potential energy of U = -2.45 x 10^-12 J, but discrepancies in results prompted further verification of the calculations.

PREREQUISITES
  • Understanding of gravitational potential energy calculations
  • Familiarity with the gravitational constant (G = 6.67 x 10^-11 Nm^2/kg^2)
  • Knowledge of basic physics concepts related to mass and distance
  • Ability to perform calculations involving scientific notation
NEXT STEPS
  • Review the derivation of the gravitational potential energy formula U = -(Gm1m2)/r
  • Explore the effects of varying distances on gravitational potential energy
  • Learn about the implications of gravitational potential energy in multi-particle systems
  • Investigate how to calculate gravitational forces between multiple masses
USEFUL FOR

Students studying physics, particularly those focusing on gravitational forces and potential energy calculations, as well as educators looking for examples of multi-particle systems in gravitational contexts.

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1. A system consists of three particles, each of mass 1.90 g, located at the corners of an equilateral triangle with sides of 31.0 cm. Calculate the potential energy of the system.

2. Homework Equations :

U= -(Gm1m2)/r

G = 6.67x10^-11 Nm^2/kg^2

3. My attempt:

I would think each particle would exert the same gravitational field on the other two particles. Therefore:

U = 3(-Gm1m2)/r

U = -2.45 x 10^-12 J
 
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Your theory is right...I'd try the calculation again. When I did it, I got a different answer.
 

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