Gravitational potential energy - problem

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SUMMARY

The discussion centers on the concept of gravitational potential energy (GPE) and its calculation when moving a mass from a distance (r1) to an infinite distance (r2) from Earth. Participants clarify that GPE is defined as the work done against gravitational force, expressed mathematically as GMm[(1/r2) - (1/r1)]. Despite initial confusion regarding the negative value of GPE when lifting a mass, it is established that the change in gravitational potential energy is positive when considering the work done on the object. The negative sign in gravitational force indicates its attractive nature, necessitating careful attention to sign conventions in calculations.

PREREQUISITES
  • Understanding of gravitational force and its mathematical representation (-GMm/(r^2))
  • Familiarity with the concept of work in physics
  • Basic knowledge of integration in calculus
  • Awareness of gravitational potential energy and its significance in physics
NEXT STEPS
  • Study the derivation of gravitational potential energy using calculus
  • Explore the implications of sign conventions in gravitational force and potential energy
  • Learn about the relationship between gravitational potential energy and kinetic energy
  • Review reliable physics textbooks or resources on gravitational concepts
USEFUL FOR

Students of physics, educators teaching gravitational concepts, and anyone seeking to deepen their understanding of gravitational potential energy and its calculations.

zinc79
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Hello. I'm new. I was looking around on the web a bit to find an answer to my problem, and I came across these forums.

Gravitational force = -GMm/(r^2)

Gravitational force between a small mass (m) and the Earth (M) is zero at a distance of infinity. Any distance smaller than infinity gives a negative value. When the distance is minimum, the force is mathematically minimum but actually the largest in magnitude. When the distance is infinite, the force is mathematically largest but actually the least in magnitude.

But what is gravitational potential energy? Is it work done due to gravitational force in moving a mass from a distance (r) to an infinite distance? Is it work done due to gravitational force in moving a mass from a an infinite distance to a distance (r)? Or is it simply the work done due to gravitational force in moving the mass from one point to another?

Now, I'll deal with a case when I move a mass (m) from a distance (r1) to an infinite distance from the Earth (r2)

The gravitational potential energy, as I have learnt, is simply the integration the the gravitational force. This comes out as GMm[(1/r2) - (1/r1)]. This is where I have the problem. If the mass gains height, i.e. moves away from the earth, then r1 is small and r2 is large, and because of this the gravitational potential energy turns out negative! Isn't it supposed to be a GAIN in potential energy? Isn't the change supposed to give a positive value? If not, then why? Work is being done ON the object to raise it, right?
 
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Gravitational potential energy is the energy something has because of it's position in a graviy field. The change is simply the change from it's original position - the total GPE would be compared to it's potential at an infinite distance but that isn't usually very useful.

The negative sign in the force is beacuse it is attractive, you have to be a little careful with the sign conventiona, see-
http://en.wikipedia.org/wiki/Gravitational_potential_energy#Gravitational_potential_energy
 
zinc79 said:
The gravitational potential energy, as I have learnt, is simply the integration the the gravitational force. This comes out as GMm[(1/r2) - (1/r1)]. This is where I have the problem. If the mass gains height, i.e. moves away from the earth, then r1 is small and r2 is large, and because of this the gravitational potential energy turns out negative! Isn't it supposed to be a GAIN in potential energy? Isn't the change supposed to give a positive value? If not, then why? Work is being done ON the object to raise it, right?
Careful. To calculate the change in gravitational PE you must integrate the force needed to lift the object over the distance r1 to r2. That force is upward and equals +GMm/(r^2). So if you calculate the work done by that force, which is the work done ON the object, you'll find that the change in gravitational PE in raising a mass will be positive, as you suspect.
 


I get you Doc Al, but wikipedia says that "Gravitational potential energy is the work of gravitational force", and well, it is a popular source... I'm still confused...
 
I wouldn't lean too heavily upon wiki as a source. Don't you have a textbook? Here's a reliable discussion of gravitational PE: Gravitational Potential Energy.
 
zinc79 said:
But what is gravitational potential energy? Is it work done due to gravitational force in moving a mass from a distance (r) to an infinite distance? Is it work done due to gravitational force in moving a mass from a an infinite distance to a distance (r)? Or is it simply the work done due to gravitational force in moving the mass from one point to another?

from my personal expierence it's all just nonsense. It really doesn't mean anything. Because they analyze lot of problems with gravitational force in them, so they name the work done by gravitational force "gravitional potential enery".

Yes, it is work done due to gravitational force while moving an object from A to B.

Edit: While solving your problems, ignoring gravitational potential energy may help you (it always helped me!)
 
zinc79 said:
because of this the gravitational potential energy turns out negative! Isn't it supposed to be a GAIN in potential energy? Isn't the change supposed to give a positive value? If not, then why? Work is being done ON the object to raise it, right?


oops, i missed this part :redface:

see the potential curve well( that would explain why it's more negative)

Yes, work is being done on the object to raise it,
but assuming that the object had some initial v at the start,
then after reaching the height the v would be reduced..

and so the system is losing its kinetic energy..
 

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