Gravitational Potential Energy Problem

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SUMMARY

The discussion addresses a gravitational potential energy problem involving the moon and Earth. The mass of Earth is specified as 5.98x10^24 kg, and the distance from the center of Earth to the center of the moon is given as 3.82x10^8 m. The correct calculation for the speed at which the moon would strike the Earth, accounting for both the Earth's radius and the moon's radius, is determined to be 9.8 km/s, correcting an initial miscalculation of 11.10 km/s.

PREREQUISITES
  • Understanding of gravitational potential energy equations
  • Familiarity with the concepts of kinetic energy and conservation of energy
  • Knowledge of the mass and radius of Earth and the moon
  • Ability to perform algebraic manipulations and substitutions in physics equations
NEXT STEPS
  • Review gravitational potential energy calculations in classical mechanics
  • Study the conservation of mechanical energy in closed systems
  • Explore the effects of varying distances on gravitational interactions
  • Investigate the implications of mass and radius in orbital mechanics
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Students studying physics, particularly those focusing on mechanics and gravitational forces, as well as educators looking for examples of gravitational potential energy problems.

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[SOLVED] Gravitational Potential Energy Problem

Homework Statement


Suppose that the moon were at rest at its present distance from the earth, rather than orbiting it. With what speed would it strike the earth? (Take the Earth to be infinitely massive relative to the moon)


Homework Equations


Mass of Earth = 5.98x10^24 kg
Distance from center of Earth to center of moon = R = 3.82x10^8 m
Mean radius of Earth = Re = 6.37x10^6 m
Gravitational potential energy = -GMm/R
K1+U1=K2+U2

The Attempt at a Solution


K1=0
k2=(1/2)Mmv^2
U1=-GMeMm/R
U2=-GMeMm/Re
(1/2)Mmv^2-GMeMm/R=-GMeMm/Re
when I eliminate the mass of the moon and plug in all the numbers to solve I get 11.10 km/s, but I know the right answer is 9.8 km/s. Anyone see what I am doing wrong?
 
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The radius of the moon?
 
a-ha! Bingo! Thank you so much. The second potential energy distance would have be the sum of the radius of the Earth AND the moon! Let's see our numbers...yep 9.8 km/s!

Thank you so much!
 
No problem, glad to see you got it. :)
 

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