Gravitationtrouble setting up equation

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The discussion focuses on maximizing the gravitational attraction between two pieces of a particle of mass M, split into masses m and M-m. The gravitational force is expressed using the formula F_g = Gm_1m_2/r^2, leading to the equation F_g = GM(M-m)/r^2. To find the optimal ratio of m/M, participants suggest optimizing the product m(M-m) by taking the derivative with respect to m and setting it to zero, which yields the optimal value of m.

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Saladsamurai
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My problem lies in setting this up.

A particle of mass M is split into two pieces, M and M-m, and are set some distance apart.

What ratio of m/M maximizes the magnitude of the gravitational attraction.

I will definitely be needing [tex]F_g=\frac{Gm_1m_2}{r^2}[/tex]

I know that after making appropriate substitutions I get.

[tex]F_g=\frac{GM(M-m)}{r^2}[/tex]
but my problem is in how to compare what happens as m-->M?

Any thoughts in the set up?

Thanks,
Casey
 
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Saladsamurai said:
My problem lies in setting this up.

A particle of mass M is split into two pieces, M and M-m, and are set some distance apart.

What ratio of m/M maximizes the magnitude of the gravitational attraction.

I will definitely be needing [tex]F_g=\frac{Gm_1m_2}{r^2}[/tex]

I know that after making appropriate substitutions I get.

[tex]F_g=\frac{GM(M-m)}{r^2}[/tex]
but my problem is in how to compare what happens as m-->M?

Any thoughts in the set up?

Thanks,
Casey


You mean that the pieces are m and M-m!
basically, you have to optimize the product m(M-m) as a function of m. Just take the derivative with respect to m and set the derivative equal to zero. That will give you the optimum m and then you may calculate the ratio m/M.
 
Last edited:
nrqed said:
You mean that the pieces afre m and M-m!
basically, you have to optimize the product m(M-m) as a function of m. Just take the derivative with respect to m and set the derivative equal to zero. That will give you the optimum m an dthen you may calculate the ratio m/M.

AWWWW! I knew that! I wrote out the product wrong! Thanks nrqed

Casey!
 

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