marcus
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Hi selfAdjoint, I wonder if anyone else is having the same trouble that I do reading LaTex.
When LaTex is typed in line there is sometimes overwriting. So this from your last post should be perfectly legible but is not because part of the algebraic expression is typed overtop the other. And it doesn't happen with complete consistency every time I view the post! Now it is not doing it. This passage comes through perfectly:
But earlier today, to make this readable I needed to insert carriage-returns after some of the LaTex to avoid having two Tex expressions on the same line. Like this:
<<...And that's what the Wick Rotation does with time. Defining t = i\tau, a pure imaginary, we have -t^2 = -(i\tau)^2 = - ((-1)\tau^2) = +\tau^2,
so you go from -c^2t^2 + x^2 + y^2 + z^2
to +c^2\tau^2 + x^2 + y^2 + z^2 with all positive signs, which allows the path integrals to converge. Then after you get the result you know you can just plug in t in it wherever \tau appears, because that smooth transition is guaranteed>>
When LaTex is typed in line there is sometimes overwriting. So this from your last post should be perfectly legible but is not because part of the algebraic expression is typed overtop the other. And it doesn't happen with complete consistency every time I view the post! Now it is not doing it. This passage comes through perfectly:
selfAdjoint said:...And that's what the Wick Rotation does with time. Defining t = i\tau, a pure imaginary, we have -t^2 = -(i\tau)^2 = - ((-1)\tau^2) = +\tau^2, so you go from -c^2t^2 + x^2 + y^2 + z^2 to +c^2\tau^2 + x^2 + y^2 + z^2 with all positive signs, which allows the path integrals to converge. Then after you get the result you know you can just plug in t in it wherever \tau appears, because that smooth transition is guaranteed.
But earlier today, to make this readable I needed to insert carriage-returns after some of the LaTex to avoid having two Tex expressions on the same line. Like this:
<<...And that's what the Wick Rotation does with time. Defining t = i\tau, a pure imaginary, we have -t^2 = -(i\tau)^2 = - ((-1)\tau^2) = +\tau^2,
so you go from -c^2t^2 + x^2 + y^2 + z^2
to +c^2\tau^2 + x^2 + y^2 + z^2 with all positive signs, which allows the path integrals to converge. Then after you get the result you know you can just plug in t in it wherever \tau appears, because that smooth transition is guaranteed>>
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