GRE: Solving "n" Integer Question: Determining Possible Values

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Discussion Overview

The discussion revolves around a GRE question regarding the possible values of a positive integer "n" based on the condition that the smallest whole number greater than or equal to n/33 is either 1 or 2. Participants explore the implications of this condition and seek to identify all valid integers for "n".

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant suggests that since the smallest whole number greater than or equal to n/33 can be 1 or 2, they derive that n must be less than 66 based on the inequality 2 > n/33.
  • Another participant questions whether 66 is the only possible value or if it is excluded from the options.
  • A later reply clarifies that any positive integer less than 66 is considered a correct answer, implying multiple values for n.
  • Participants agree that since 2 is greater than 1, only the condition related to 2 needs to be considered for determining possible values of n.

Areas of Agreement / Disagreement

Participants generally agree that any positive integer less than 66 is a valid solution for n. However, there is some initial confusion about whether 66 itself is included as a possible value.

Contextual Notes

The discussion does not resolve the implications of the smallest whole number condition in detail, nor does it clarify the treatment of boundary values like 66.

Who May Find This Useful

Students preparing for the GRE, particularly those focusing on quantitative reasoning and integer problems.

CharlesLin
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I'm studying for the GRE and got stuck on this question

Suppose "n" is a positive integer such that the smallest whole number that is greater than or equal to n/33 is 1 or 2. which are possible values for the integer n? indicate all such integers.

a 15
b 24
c 50
d 66
e 77

what i start doing was giving values to "n" like n=15 then 15/33= .45 the this is not a possible value of "n" because the answer is not a whole number. following this logic, the only possible answer to me is d= 66. However my guide book saids ther more than that possble value for "n". How would you recommend to anwer this question?
 
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The way I read the problem, we have either:

$$1>\frac{n}{33}$$

or

$$2>\frac{n}{33}$$

And since $2>1$, we need only consider:

$$2>\frac{n}{33}$$

This implies:

$$66>n$$
 
so are you saying that the only answer is 66 or that this is the only one that is not an answer?
 
I am saying any positive integer less than 66 is correct. :D
 
We only consider 2 because is larger than one. Then we have

2>n/33
33*2= 66

66>n

Any number less than 66 is value of “n”

Thank you very much!
 

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