MHB GRE: Solving "n" Integer Question: Determining Possible Values

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The discussion revolves around determining possible values for the positive integer "n" based on the condition that the smallest whole number greater than or equal to n/33 is either 1 or 2. It is established that if 2 is the only relevant threshold, then n must be less than 66. Participants clarify that any positive integer less than 66 satisfies the condition, not just 66 itself. The initial confusion regarding the values of n is resolved by recognizing that all integers from 1 to 65 are valid solutions. The conclusion emphasizes that any positive integer less than 66 is acceptable for n.
CharlesLin
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I'm studying for the GRE and got stuck on this question

Suppose "n" is a positive integer such that the smallest whole number that is greater than or equal to n/33 is 1 or 2. Wich are possible values for the integer n? indicate all such integers.

a 15
b 24
c 50
d 66
e 77

what i start doing was giving values to "n" like n=15 then 15/33= .45 the this is not a possible value of "n" because the answer is not a whole number. following this logic, the only possible answer to me is d= 66. However my guide book saids ther more than that possble value for "n". How would you recommend to anwer this question?
 
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The way I read the problem, we have either:

$$1>\frac{n}{33}$$

or

$$2>\frac{n}{33}$$

And since $2>1$, we need only consider:

$$2>\frac{n}{33}$$

This implies:

$$66>n$$
 
so are you saying that the only answer is 66 or that this is the only one that is not an answer?
 
I am saying any positive integer less than 66 is correct. :D
 
We only consider 2 because is larger than one. Then we have

2>n/33
33*2= 66

66>n

Any number less than 66 is value of “n”

Thank you very much!
 

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