GRE: Solving "n" Integer Question: Determining Possible Values

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The discussion focuses on solving a GRE problem regarding the possible values of a positive integer "n" based on the condition that the smallest whole number greater than or equal to n/33 is either 1 or 2. The analysis reveals that any positive integer less than 66 satisfies this condition. The only incorrect assumption made was that 66 is the only possible value, while in fact, all integers from 1 to 65 are valid solutions.

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CharlesLin
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I'm studying for the GRE and got stuck on this question

Suppose "n" is a positive integer such that the smallest whole number that is greater than or equal to n/33 is 1 or 2. which are possible values for the integer n? indicate all such integers.

a 15
b 24
c 50
d 66
e 77

what i start doing was giving values to "n" like n=15 then 15/33= .45 the this is not a possible value of "n" because the answer is not a whole number. following this logic, the only possible answer to me is d= 66. However my guide book saids ther more than that possble value for "n". How would you recommend to anwer this question?
 
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The way I read the problem, we have either:

$$1>\frac{n}{33}$$

or

$$2>\frac{n}{33}$$

And since $2>1$, we need only consider:

$$2>\frac{n}{33}$$

This implies:

$$66>n$$
 
so are you saying that the only answer is 66 or that this is the only one that is not an answer?
 
I am saying any positive integer less than 66 is correct. :D
 
We only consider 2 because is larger than one. Then we have

2>n/33
33*2= 66

66>n

Any number less than 66 is value of “n”

Thank you very much!
 

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