- #1

ehrenfest

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## Homework Statement

Please stop reading unless you have Griffith's E and M book (3rd Edition).

Maybe I am nitpicking, but I think the sign is wrong on the last equation on page 80. The formula for the potential was

[tex] V(\vec{r}) = -\int_{O}^{\vec{r}}\vec{E}\cdot d\vec{l} [/tex]

Thus when you come in from z = infinity along the z axis [itex] \vec{E}\cdot d\vec{l} [/itex] becomes E(-dz) right ?