Group of 3x3 Matrices w/o Center - Complex & Real Numbers

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The discussion centers on the group of 3x3 matrices defined as [e^t 0 u; 0 e^(tx) v; 0 0 1], where t and u, v are complex numbers and x is a real number. Participants debate whether this group has a center, concluding that while every group has a center, it can be trivial. The argument presented suggests that by demonstrating two commuting matrices, one can infer they must both be the identity matrix, thus indicating the center is trivial in this case.

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arz2000
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Hi all,
can you show that the group of all 3 by 3 matrices
[e^t 0 u
0 e^xt v
0 0 1]
where t, u, v are in C (complex numbers) and x is in R (real number)
has no center?

Regards
 
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I mean all 3 by 3 matrices with the following rows
(e^t, 0, u)
(0, e^(tx), v)
(0, 0, 1).
 
You can't, since it does have a centre - every group has a centre, possibly trivial (as it is in this case).

You just write down two matrices, suppose the commute and show that this implies that they are both the identity matrix.
 

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