GUTs: Understanding SU(5), SO(10) & E6

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SUMMARY

The discussion focuses on Grand Unified Theories (GUTs), specifically SU(5), SO(10), and E6. It highlights the structure of SU(5), which has a root system A_4 and 24 generators of the Lie algebra. The conversation clarifies that not all generators are utilized; instead, a diagonal representation is employed to achieve spontaneous symmetry breaking into SU(3) x SU(2) x U(1) through a Higgs field in the adjoint representation. Srednicki's Quantum Field Theory book is recommended as a resource for understanding the SU(5) model.

PREREQUISITES
  • Understanding of Lie algebras and their generators
  • Familiarity with the concepts of gauge bosons and symmetry breaking
  • Knowledge of the Standard Model of particle physics
  • Basic comprehension of Quantum Field Theory (QFT)
NEXT STEPS
  • Study the structure of SU(5) and its role in Grand Unified Theories
  • Explore the concept of spontaneous symmetry breaking in particle physics
  • Read Srednicki's Quantum Field Theory for foundational knowledge
  • Investigate the implications of SO(10) and E6 in GUTs
USEFUL FOR

Physicists, particularly those specializing in theoretical physics, particle physics researchers, and students studying Grand Unified Theories and Quantum Field Theory.

Jim Kata
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I don't have access to Georgi's and Wilcheck's work, if somebody has some good links to an overview of the su(5), so(10), and e6 GUTS that would be awesome.

Anyways, there's something I really don't get, let's take su(5) for example, su(5) has the root system A_4 now there is 4(4+2) = 24 generators of the lie algebra. Now I know they didn't use all 24 of the generators because it would mean that there were 24 gauge bosons, not including the Higgs. So I heard they used a diagonal representation of su(5). Something like

[su(3)0]
[0 su(2)]

Does that entail just using the Cartan subalgebra or what? What did they do?
 
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All 24 gauge bosons are there, but SU(5) is spontaneously broken to SU(3)xSU(2)xU(1) by a vacuum expectation value for a Higgs fields in the adjoint representation.

Srednicki's QFT book (available free on his website) has a good basic discussion of the SU(5) model.
 
Jim Kata said:
I don't have access to Georgi's and Wilcheck's work, if somebody has some good links to an overview of the su(5), so(10), and e6 GUTS that would be awesome.

Anyways, there's something I really don't get, let's take su(5) for example, su(5) has the root system A_4 now there is 4(4+2) = 24 generators of the lie algebra. Now I know they didn't use all 24 of the generators because it would mean that there were 24 gauge bosons, not including the Higgs. So I heard they used a diagonal representation of su(5). Something like

[su(3)0]
[0 su(2)]

Does that entail just using the Cartan subalgebra or what? What did they do?

I'm not at all a specialist of GUT, but I think only generators from SU3 x SU2 x U1 are diagonal and commute. Other generators are non-diagonal and entail the breaking of SU5 into SU3 x SU2 x U1.
If you have good www ressources, I'm also interested.
 

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