Half Angle Formula: Solving the Homework Statement

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tweety1234
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Homework Statement



Can someone please explain how my book got [itex]sin^{2} \theta = \frac{1-cos2\theta}{2}[/itex] and [itex]cos^{2}\theta = \frac{1+cos2\theta}{2}[/itex]

As I thought the half angle formula's were [itex]sin \frac{\theta}{2} = \sqrt{\frac{1-cos\theta}{2}}[/itex]

[itex]cos\frac{\theta}{2} = \sqrt\frac{1+cos\theta}{2}}[/itex]

So how can it also be the top one's aswell?

Thanks.
 
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Doc Al said:
Replace θ with 2θ.


Oh I see, can't believe I missed that.

Thanks.