Half Reaction Problem: Get Help Here

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fasterthanwoo
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Thanks for the help guys.
 
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You need equal amounts of the elements O and H on both sides of the equation. Try adding H2O on the left side and balance the elements, then balance the charges.
 
Thanks for the help guys.
 
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fasterthanwoo said:
I am still having some trouble with this.

The MnO4 is being reduced.

The oxidation state of MnO4 is 7. The oxidation state of MnO2 is 4. Therefore I need three e- to reduce?

Is it needed to have H2O on the left side of the reaction?

Thank you.

Yes. Three electrons to reduce Mn. Now balance the electrons for both half-reactions before worrying about the H's and the O's and the H2O's.
 
Thanks for the help guys.
 
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