Chemistry Halogenation of an alcohol (iodation)

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To convert an alcohol (ROH) to an iodide (RI), using the Finkelstein reaction is preferred over direct iodination with PI3 due to cost considerations. The process involves first converting ROH to RBr using PBr3, followed by a reaction with NaI to yield RI and NaBr. While direct iodination with PI3 or HI is possible, it may not be economically viable. The discussion emphasizes the importance of evaluating the cost-effectiveness of different methods. Understanding these reactions is crucial for efficient synthesis in organic chemistry.
duchuy
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Homework Statement
Turn R-OH to R-I
Relevant Equations
x
I don't understand why in order to make RI from ROH, you'd have to use FINSKELSTEIN condition:
ROH + PBR3 --> RBr
RBr + NaI --> RI + NaBr

and not directly
ROH + PI3 --> RI

Thank you so much for your help!
Pardon me if my english is not correct.

<mentor edit>
 
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