Hardy Cross method correction problem

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Homework Statement

I have problem with the flow rate (Q) in junction that join 2 loops together , where k = 4 ,

Why in the second correction , the corrected Q in first and second loop = 21 clcockwise for left loop , and for 21 anticlockiwise for right loop ?

Homework Equations

The Attempt at a Solution

IMO, it should be 10+2 = 12 for the left loop , and for the right loop , it should be -10-9= -19 , am I right ?[/B]

 

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