Hardy Cross method correction problem

  • #1

Homework Statement


I have problem with the flow rate (Q) in junction that join 2 loops together , where k = 4 ,

Why in the second correction , the corrected Q in first and second loop = 21 clcockwise for left loop , and for 21 anticlockiwise for right loop ?



Homework Equations




The Attempt at a Solution


IMO, it should be 10+2 = 12 for the left loop , and for the right loop , it should be -10-9= -19 , am I right ??????[/B]
 

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  • #3
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