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Hardy Cross method correction problem

  1. May 22, 2016 #1
    1. The problem statement, all variables and given/known data
    I have problem with the flow rate (Q) in junction that join 2 loops together , where k = 4 ,

    Why in the second correction , the corrected Q in first and second loop = 21 clcockwise for left loop , and for 21 anticlockiwise for right loop ?

    2. Relevant equations

    3. The attempt at a solution
    IMO, it should be 10+2 = 12 for the left loop , and for the right loop , it should be -10-9= -19 , am I right ??????

    Attached Files:

  2. jcsd
  3. May 24, 2016 #2
  4. May 25, 2016 #3
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