Heat calculation for ligand-protein binding equilibrium with initial product

[Icecream]

Anybody can help for calculation of the heat of the following reaction?

Some background:
Ligand X bind to protein M, the product is MX. Binding affinity of X to M is K = [MX]/([M]*[X]).
[MX], [M], [X] are the concentrations of each stuff after the reaction finished.
The ratio of MX to total M is θ = [MX]/([M]+[MX]).
ΔH is the molar heat of M, V is the volume of reaction.
Mt and Xt is the concentration of total M and X at the beginning of the reaction.
So, for this reaction the heat Q = θ*Mt*ΔH*V

My Question is:
The beginning products: Xt= 50 uM, Mt=400 uM, also some [MX] = 4 um, ( Mt is the total concentration of M, including the M in MX),
V=200 ul, K= 100000 M^-1, and ΔH =-4000
How to calculate the heat Q for above reaction?

Tons of thanks!

 

[Borek]

ΔH is the molar heat of M

No idea what you mean by that.

And no idea what the problem is - you are given equation, you are given data, why don't you plug the numbers in?

 

[Icecream]

Thanks for your post.

The equation I have is only for M and X at the beginning of the reaction. My question now is there is small amount of MX mixed in the beginning.

 

[Icecream]

I guess it is hard to calculate θ, just leave it in the final answer

 

[Borek]

Isn't it just a trivial equilibrium problem? Easily solved with an ICE chart? You are given K, you know the reaction equation, you know starting concentrations.

 

[Icecream]

Thanks! I will try the ICE chart.