Heat required to warm ice from -25°C to water at 25°C

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new324
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Allright, I may sound stupid on this one.
How much heat (Q) is required to change 456 g of ice at -25(degrees celsius) into water at 25(degrees C). The Specific heat of ice is 2090 J/kg K, the specific heat of water is 4186 J/kg K. The latent heat of fusion of water is 33.5*10^4 J/kg.

Is this just going to be Qwater+Qice+Qlatent? Where Qlatent is m*L?
 
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[tex]Q = cm\Delta T[/tex]

and

[tex]Q = mH_f[/tex]

I think you have the right idea, but your notation is a little awkward.

cookiemonster