1. The problem statement, all variables and given/known data How long would a 3.50 kW space heater have to run to put into a kitchen the same amount of heat as a refrigerator (coefficient of performance = 3.13) does when it freezes 1.46 kg of water at 21.4°C into ice at 0°C? m=1.46 kg c_water=4186 J/kg Delta T= 21.4°C L_fusion= 3.34x10^5 J/kg COP= 3.13 P= 3.50 kW 2. Relevant equations Q_c = m x c_water x Delta T + m x L_f COP = Q_c/W P = W/t 3. The attempt at a solution I plugged everything into the equation for the heat and got 618427 J. Then I divided that by the coefficient of performance to get that work = 197581 J. Then, I divided that by 3500 W for the power and found that t = 56.45 s. And apparently that's not the answer. I'm not sure where I went wrong!