Height of pier above water- projectile motion

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SUMMARY

The discussion centers on calculating the height of a pier above water based on a swimmer's dive. The swimmer, moving at a velocity of 1.80 m/s, hits the water 0.80 m from the pier's edge. The calculations involve using the equations of motion: dh = Vh * Δt and dv = 1/2 * a * t², resulting in a time of flight (Δt) of 0.44 seconds and a vertical distance (dv) of 0.97 m. All calculations were confirmed to be correct with respect to significant figures.

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  • Understanding of basic kinematics in physics
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  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Ability to perform calculations involving significant figures
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dani123
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Homework Statement



A swimmer moving at 1.80m/s, dives off a pier and hits the water 0.80m from the edge of the pier. How high is the pier above the water?


Homework Equations



dv=1/2*at2
dh=Vh*Δt
a=9.8

The Attempt at a Solution



dh=0.80m
Vh=1.80m/s
dv=?
t=?

First started by solving for Δt in the dh=Vh*Δt equation and found that Δt=0.44s

Then I plugged it into the dv=1/2*at2 equation

dv=0.97m

I would like for someone to just verify that my answers are correct and the significant figures are being respected. Thanks in advance!
 
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yep, all correct. very good.
 

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